8x^2+100x+144=0

Solution for 8x^2+100x+144=0 equation:

8x^2+100x+144=0

a = 8; b = 100; c = +144;
Δ = b2-4ac
Δ = 1002-4·8·144
Δ = 5392
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{5392}=\sqrt{16*337}=\sqrt{16}*\sqrt{337}=4\sqrt{337}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(100)-4\sqrt{337}}{2*8}=\frac{-100-4\sqrt{337}}{16}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(100)+4\sqrt{337}}{2*8}=\frac{-100+4\sqrt{337}}{16}
$